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Find the current flowing through 6 ohm resistor |
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Answer» Answer: Explanation: The given circuit ACT as a balanced wheatstons BRIDGE[no current through the wire connecting the TWO resistor combination] since it SATISFIES the condition 3/6=12/24=1/2. net resistance, 3 and 12 are in series=15 ohm 6 and 24 are in series =30 ohm this 15 and 30 are in parallel net resistance=10 ohm net current,V=IR 30V=I*10,I=3A current in 6 ohm= current in 24 ohm since in series connection branch 1 [3 and 12] and branch 2[6 and 24] are in same voltage due to parallel connection current through the 6 ohm is 5 A |
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