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Find the current flowing through 4Ω resistor shown in network below.(a) 1.33A(b) 2.35A(c) 1.66A(d) 2.66AThe question was posed to me during an interview for a job.This key question is from Source Transformations in section Techniques of Circuit Analysis of Electric Circuits

Answer»

Right option is (c) 1.66A

Easiest explanation: By using SOURCE transformation the above network is REDUCED and then by CURRENT DIVISION rule I4Ω= 5*(2/2+4) =1.66A.



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