1.

Find the cubes of the following numbers by column method:(i) 35(ii) 56

Answer»

(i) 35

We have, a = 3 and b = 5

Column I
a3
Column II
3 × a2 × b
Column III
3 × a × b2
Column IV
b3
33 = 273×9×5 = 1353×3×25 = 22553 = 125
+15+23+12+125
42158237
42875
 

∴ The cube of 35 is 42875

(ii) 56

We have, a = 5 and b = 6

Column I
a3
Column II
3 × a2 × b
Column III
3 × a × b2
Column IV
b3
53 =1253×25×6 =4503×5×36 = 54063 = 216
+50+56+21123
175506561
175616

∴ The cube of  56 is 175616



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