1.

Find the cubes of: (i) -11 (ii) -12 (iii) -21

Answer»

(i) \(-11\)

 = \((-11)^3 = -11\times-11\times-11=-1331\)

(ii) \(-12\)

 = \((-2)^3 =-12\times-12\times-12=-1728\)

(iii) \(-21\)

 = \((-21)^3 = -12\times-21\times-21=-9261\)



Discussion

No Comment Found