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Find the cube root of each of the following numbers:(i) 8×125 (ii) -1728×216 |
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Answer» (i) 8×125 We know that for any two integers a and b, ∛(a×b) = ∛a × ∛b By using the property, ∛ (8×125) = ∛8 × ∛125 = ∛(2×2×2) × ∛(5×5×5) = 2×5 = 10 (ii) -1728×216 We know that for any two integers a and b, ∛(a×b) = ∛a × ∛b By using the property, ∛(-1728×216) = ∛-1728 × ∛216 We shall use the unit digit method, Let the number 1728, where Unit digit = 8 The unit digit in the cube root of 1728 will be 2 After striking out the units, tens and hundreds digits of the given number, we are left with the 1. We know 1 is the largest number whose cube is less than or equal to 1. So, the tens digit of the cube root of 1728 = 1 ∛1728 = 12 Now, let’s find the prime factors for, 216 = 2×2×2×3×3×3 By grouping the factors in triples of equal factor, we get, 216 = (2×2×2) × (3×3×3) ∛216 = 2×3 = 6 From above we take as, ∛(-1728×216) = ∛-1728 × ∛216 = -12 × 6 = -72 |
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