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Find the cube of:(i) \(3\frac{1}{4}\) (ii) 0.3 (iii) 1.5 (iv) 0.08 (v) 2.1 |
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Answer» (i) \(3\frac{1}{4}\) = \((3\frac{1^3}{4})\) = \((\frac{13}{4})^3 = \frac{2197}{64}\) (ii) \(0.3\) = \((0.3)^3 = 0.3\times0.3\times0.3 = 0.027\) (iii) \(1.5\) = \((1.5)^3 = 1.5\times1.5\times1.5 = 3.375\) (iv) \(0.08\) = \((0.08)^3 = 0.08\times0.08\times0.08 = 0.000512\) (v) 2.1 \((2.1)^3 = 2.1\times2.1\times2.1 = 9.261\) |
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