Find the corcinate of point of linejoining point (2, 3) and (4, 6)whic

1.	Find the corcinate of point of linejoining point (2, 3) and (4, 6)which diveds the ratio 1:3 internaly
Answer» Answer:Given:- A(x₁, y₁) = (2, 3) B(x₂, y₂) = (4, 6) m : N = 1 : 3 internally. To find:- P(α, β) = ? Answer:- We have to use the section formula for internal division. It says that, If P(α, β) divides a line segment AB with A(x₁, y₁) and B(x₂, y₂) internally in the RATIO m : n, then, α = [(mx₂ + nx₁) / (m + n)] β = [(my₂ + ny₁) / (m + n)] According to the question, putting the VALUES as, x₁ = 2 y₁ = 3 x₂ = 4 y₂ = 6 m = 1 n = 3 Putting the values in the formula, ▪α = [(mx₂ + nx₁) / (m + n)] → α = [ {(1 × 4) + (3 × 2)} / (1 + 3) ] → α = [ {4 + 6} / 4 ] → α = 10/4 → α = 2.5 And, ▪β = [(my₂ + ny₁) / (m + n)] → β = [ {(1 × 6) + (3 × 3)} / (1 + 3)] → β = [ {6 + 9} / {4} ] → β = 15/4 → β = 3.75 So, → P(α, β) = (2.5, 3.75) Ans. Step-by-step explanation:

Find the corcinate of point of linejoining point (2, 3) and (4, 6)which diveds the ratio 1:3 internaly

Answer»

Answer:Given:-

A(x₁, y₁) = (2, 3)

B(x₂, y₂) = (4, 6)

m : N = 1 : 3 internally.

To find:-

P(α, β) = ?

Answer:-

We have to use the section formula for internal division. It says that,

If P(α, β) divides a line segment AB with A(x₁, y₁) and B(x₂, y₂) internally in the RATIO m : n, then,

α = [(mx₂ + nx₁) / (m + n)]

β = [(my₂ + ny₁) / (m + n)]

According to the question, putting the VALUES as,

x₁ = 2

y₁ = 3

x₂ = 4

y₂ = 6

m = 1

n = 3

Putting the values in the formula,

▪α = [(mx₂ + nx₁) / (m + n)]

→ α = [ {(1 × 4) + (3 × 2)} / (1 + 3) ]

→ α = [ {4 + 6} / 4 ]

→ α = 10/4

→ α = 2.5

And,

▪β = [(my₂ + ny₁) / (m + n)]

→ β = [ {(1 × 6) + (3 × 3)} / (1 + 3)]

→ β = [ {6 + 9} / {4} ]

→ β = 15/4

→ β = 3.75

So,

→ P(α, β) = (2.5, 3.75) Ans.

Step-by-step explanation: