1.

find the coordinates of the points lying on the y--axis,P(0 , y),when the distance between points P and A (5,4) is 13

Answer»

Step-by-step EXPLANATION:

distance \: formula \\ \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} }

pa = \sqrt{(5 - 0) {}^{2} + (4 - y) {}^{2} } = 13 \\ = > \sqrt{25 + 16 + y {}^{2} - 8y} = 13 \\ = > \sqrt{41 + y {}^{2} - 8y} = 13 \\ = > 41 + y {}^{2} - 8y = 13 { }^{2}

= > y {}^{2} - 8y + 41 - 169 = 0 \\ = > y {}^{2} - 8y - 128 = 0 \\

.......y = 16(or)y = 8 \\ the \: points \: lying \: on \: the \: y-axis \: is \: y = 8y \: (or)= 16


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