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Find the coordinates of a point the parabola `y^(2)=8x` whose distance from the focus is 10. |
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Answer» Distance of point P(x,y) from the focus S(a,0) of the parabola `y^(2)=4ax` is SP = a+x. Also, given that SP=10. `:.` 10=2+x `:.` x=8 So, from `y^(2)=8x`, `y^(2)=64` `:. " "y=pm8` So, coordinates of point P are (8,8) or (8,-8). |
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