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Find the constant k so that the planes x-2y+kz=0 and 2x+5y-z=0 are at the right anglesPls answer it fast |
Answer» given planes are at right angle if k = -8Step-by-step explanation: x - 2y + KZ = 0 2x + 5y - z=0 Cos θ = | 1 * 2 + (-2)*5 + k(-1) / (√( 1² + (-2)² + k² * √2² + 5² +(-1)²) Angle between these planes would be 90° => θ = 90° => Cos 90° = 0 => 0 =| 1 * 2 + (-2)*5 + k(-1) / (√( 1² + (-2)² + k² * √2² + 5² +(-1)²) => 1 * 2 + (-2) * 5 + k(-1) = 0 => 2 - 10 - k = 0 => - 8 - k = 0 => k = - 8 given planes are at right angle if k = -8 Learn more: ANGLES between PLANE 3x-4y+5z =0 and 2x-y-2z=5 - Brainly.in the acute angle between the two planes x+y+2z=3 and 3x-2y+2z=7 is. |
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