1.

Find the condition that zeroes of polynomiql p(x) = ax2+bx+c are reeiprocal of each other​

Answer»

Answer:

c=a

Step-by-step EXPLANATION:

Let the roots be m and \frac{1}{m}\\

Now, we KNOW that

Sum of roots(S) = \frac{-(Coefficient of <klux>X</klux>)}{Coefficient of x^{2} }}

And

PRODUCT of roots(P) = \frac{Constant}{Coefficient of x^{2} }

From these we get

S=-b/a

P=c/a

But product of roots = m x 1/m =1

Hence,

c/a = 1

⇒c=a


Discussion

No Comment Found

Related InterviewSolutions