1.

find the compound interest on rupees 14,000 for 1 whole 1/2 years at 12 p.a. if the interest is compound half yearly​

Answer»

Answer:

1730.4

Step-by-step explanation:

RATE of interest = 12% per YEAR

= 6% for 1/2 year

p=14,000

T=1 year = 2× 1/2years

n=2

A=p(1+r)^n

=14000(1+6%)^2

=14000× (1.06^2)

=15730.4

compound interest = 15730.4-14000=1730.4



Discussion

No Comment Found

Related InterviewSolutions