1.

Find the compound interest on rs.25000 at rate of 12 percent per annum for three years

Answer»

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Compound\:Interest=10,123.2\:rupees}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline \bold{<klux>GIVEN</klux>: }} \\  \tt:  \implies Principal(p) = 25,000 \: rupees \\  \\  \tt:  \implies Rate\%(r) = 12\% \\  \\ \tt:  \implies Time(t) = 3 \: years \\  \\ \red{\underline \bold{To \: Find: }} \\  \tt:  \implies Compound \: Interest = ?

ACCORDING to given QUESTION :

\bold{As \: we \: know \: that}  \\  \tt:  \implies A = p(1 +  \frac{r}{100} )^{t}  \\  \\ \tt:  \implies A =25000(1 +  \frac{12}{100} )^{3}  \\  \\ \tt:  \implies A =25000 \times (1 + 0.12)^{3}  \\  \\ \tt: \implies  A=25000\times (1.12)^{3}  \\  \\ \tt:  \implies A = 25000 \times 1.404928 \\  \\  \green{\tt:  \implies A =35,123.2 \: rupees} \\  \\  \bold{For \: compound \: Interest} \\  \tt:  \implies C.I = A - p \\  \\  \tt:  \implies C.I= 35123.2 - 25000 \\  \\   \green{\tt:  \implies C.I =10,123.2 \: rupees}



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