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Find the compound interest on ₹16000 for 2 years at 5% |
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Answer» ution!!<P> The concept of compound interest has to be used here. The principal, rate of interest and time is given. We have to find the compound interest. LET's find it without the formula first!! For 1st yearPrincipal (P) = Rs 16000 Time (T) = 2 year yearRate of interest (R) = 5% Interest = (P × R × T)/100 Interest = (16000 × 5 × 1)/100 Interest = Rs 800 Amount = Principal + Interest Amount = Rs 16000 + Rs 800 Amount = Rs 16800 The amount in the 1st year is the principal of the 2nd year. For 2nd yearPrincipal (P) = Rs 16800 Time (T) = 1 year Rate of interest (R) = 5% Interest = (P × R × T)/100 Interest = (16800 × 5 × 1)/100 Interest = Rs 840 Amount = Principal + Interest Amount = Rs 16800 + Rs 840 Amount = Rs 17640 Compound interest = Rs 800 + Rs 840 Compound interest = Rs 1640 Now, let's solve this using formula!! Principal (P) = Rs 16000 Time (N) = 2 year Rate of interest (R) = 5% Amount = P(1 + (R/100))² Here 2 is the time (n). Amount = 16000(1 + (5/100))² Amount = 16000(105/100)² Amount = 16000(21/20)² Amount = 16000 × (21/20) × (21/20) Amount = 160 × (21/2) × (21/2) Amount = 40 × 21 × 21 Amount = Rs 17640 CI = Amount - Principal CI = Rs 17640 - Rs 16000 CI = Rs 1640 Compound interest = Rs 1640 |
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