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Find the complement of the following Boolean function : F1 = AB’ + C’D’ |
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Answer» (AB’ + C’D’)’ = (AB’)’.(C’D’)’ (De Morgan’s first theorem) = (A’ + B’’).(C’’ + D’’) (DeMorgan’s second theorem i.e., (A.B)’= A’+ B’) = (A’ + B’).(C + D) ((X’)’= X) |
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