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Find the central angle if length of Arc is equal to 44 metre and radius is equal to 35 metre ​

Answer»

\bf \blue{hey \: user \: here \: is \: answer} \\ \\ \bf \green{ \huge \: solution} \\ \\ \bf \pink{ \underline{ \boxed{ \bf \: according \: to \: question}}} \\ \\ \: \bf \pink{given \: that} \\ \\ \bf \orange{length \: of \: arc \: (l) =44 \: m } \\ \\ \bf \pink{}\\ \\ \bf \red{r = 35 \: m} \\ \\ \bf \purple{ using \: this \: formula} \\ \\ \bf \pink{length \: of \: arc = 2\pi \: r \: \frac{ϑ}{360} } \\ \\ \bf \pink{44 = 2 \times \frac{22}{7} \times 35 \times \frac{ϑ}{360} } \\ \\ \bf \pink{44 = \frac{2 \times2 2}{ \cancel{7}} \times \cancel{7 } \times 5 \times \frac{ϑ}{360} } \\ \\ \bf \pink{ \frac{44}{2 \times 22 \times 5} = \frac{ϑ}{360} } \\ \\ \bf \pink{ \frac{44}{44 \times 5} = \frac{ϑ}{360} } \\ \\ \bf \pink{ \frac{ \cancel{44}}{ \cancel{44} \times 5} = \frac{ϑ}{360} } \\ \\ \bf \pink{ \frac{1}{5} = \frac{ϑ}{360} } \\ \\ \bf \pink{5 \:ϑ = 360 } \\ \\ \bf \pink{ϑ = \frac{360}{5} } \\ \\ \bf \pink{ϑ = 72 \degree} \\ \\ \\ \bf \red{ \therefore \: answer \: is72 \degree \: } \\ \\


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