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Find the center of mass(x,y,z) of the following structure of four identical cubes if the length of each side of a cube is 1 unit. A. `(1//2,1//2,1//2)`B. `(1//3,1//3,1//3)`C. `(3//4,3//4,3//4)`D. `(1//2,3//4,1//2)` |
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Answer» Correct Answer - C Ans. (3) First we find the center of mass of each cube. It is located by symmetry`:` `(0,5,0,5,0,5)`,`(1,5,0,5,0,5)`,`(0,5,1,5,0,5,)`,`(0,5,0,5,1.5)` Now we find the center of mass by treating the COM of each cube as a point particle`:` `x_(COM)=(0.5+1.5+0.5+0.5)/(4)=0.75` `y_(COM)=(0.5+0.5+1.5+0.5)/(4)=0.75` `z_(COM)=(0.5+0.5+0.5+1.5)/(4)=0.75` |
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