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Find the Cartesian equation of the plane passing through A(1, -2, 3) and the direction ratios of whose normal are 0, 2, 0. |
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Answer» The Cartesian equation of the plane passing through (x1, y1, z1), the direction ratios of whose normal are a, b, c, is a(x – x1) + b(y – y1) + c(z – z1) = 0 ∴ the cartesian equation of the required plane is o(x + 1) + 2(y + 2) + 5(z – 3) = 0 i.e. 0 + 2y – 4 + 10z – 15 = 0 i.e. y + 2 = 0. |
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