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Find the argument of 1+√3i/√3+I |
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Answer» Answer: Step-by-step EXPLANATION: multiply NUMERATOR and denominator by √3 - i so (1+√3i)(√3 - i) =2√3+2i and (√3 + i)(√3 - i)=4 so arg(√3/2 +i/2) so tanx =-(1/2)/(√3/2)=-1/√3 |
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