Find the area of the triangle whose vertices are A(4, 3) B(5, 4) c(11,

1.	Find the area of the triangle whose vertices are A(4, 3) B(5, 4) c(11, 2)
Answer» Answer: AREA of triangle=-7 Step-by-step explanation: x1=4,x2=5,x3=11;y1=3,y2=4,y3=2 area of triangle=1/2[x1(y3-y2)+x2(y2-y1)+x3(y1-y2)] =1/2[4(2-4)+5(4-3)+11(3-4)] =1/2[4(-2)+5(1)+11(-1)] =1/2[-8+5-11] =1/2[-19+5] =1/2[-14] =-7 hope it MAY help u.. mark me as BRAINLIEST.

Find the area of the triangle whose vertices are A(4, 3) B(5, 4) c(11, 2)

Answer»

Answer:

AREA of triangle=-7

Step-by-step explanation:

x1=4,x2=5,x3=11;y1=3,y2=4,y3=2

area of triangle=1/2[x1(y3-y2)+x2(y2-y1)+x3(y1-y2)]

=1/2[4(2-4)+5(4-3)+11(3-4)]

=1/2[4(-2)+5(1)+11(-1)]

=1/2[-8+5-11]

=1/2[-19+5]

=1/2[-14]

=-7

hope it MAY help u..

mark me as BRAINLIEST.

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Find the area of the triangle whose vertices are A(4, 3) B(5, 4) c(11, 2)​

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Find the area of the triangle whose vertices are A(4, 3) B(5, 4) c(11, 2)