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Find the area of the triangle, whose vertices are (2,1), (4,5) and (6,3). |
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Answer» Area of triangle `=1/2[x_(x)(y_(2)-y_(3))+x_(2)(y_(3)-y_(1))+x_(3)(y_(1)-y_(2))]` `=1/2[2(5-3)+4(3-1)+6(1-5)]=1/2(4+8-24)= -6` But the area of triangle connot be negative `therefore" "` Area of triangle = 6 square units |
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