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Find the area of the triangle formed by the point(-10,-4) (-8,-1) (-3-5) |
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Answer» Given (-10,-4)(-8,-1)(-3,-5) area of triangle formula 1/2 |x1 (y2-y3)+x2 (y3-y1)+x3 (y1-y2)| take -10 as x1,-4 as y1,-8 as x2,-1 as y2,-3 as x3,-5 as y3 than 1/2|-10 (-1-(-5))+(-8)(-5-(-4))+(-3)(-4-(-1))| 1/2|-10 (-1+5)+(-8)(-5+4)+(-3)(-4+1)| 1/2|-10 (+4)+(-8)(-1)+(-3)(-3)| 1/2|40+8+9| 1/2|57| |28.5| |
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