1.

Find the area of the shaded portion in figure​

Answer»

Answer:

area of SHADED PORTION =2×area of quadrant

ar(shaded region)=area of SEMICIRCLE (SINCE 2×1/4=1/2)

area = \frac{1}{2} \times \pi \times {r }^{2} \\ area = \frac{1}{2} \times \frac{22}{7} \times 14 \times 14 \\ area = 22 \times 14 = 308 {cm}^{2}

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