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find the area of the region in the first quadrant enclased by the X-arcis the line y=x the circle x2 + y2 =32 |
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Answer» Step-by-step EXPLANATION: r=32−−√=42–√ y=r=42–√ 2y2=32 y2=16 y=4 area=∫4032−x2−−−−−−√−xdx =∫40(4R)2−x2−−−−−−−−−√dx−∫40xdx =(4π−8)−[x22]40 =4π−8−[16−02] =4π−8−8 =4π−16. |
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