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Find the area of the quadrilateral AC=10cm BE=4cm DF=2cm |
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Answer» Step-by-step explanation: ANSWER: We assume ABCD be the quadrilateral having SIDES AB, BC, CD, DA and ∠ACB = 90∘. We take a diagonal AC, where AC divides ABCD into TWO triangles ΔACB and ΔADC Since ∆ACB is right angled at C, we have AC = 15 cm; AB = 17 cm AB2 = AC2 + BC2
AREA of right angled triangle ABC, say A1 is given by , where, Base = BC = 8 cm; Height = AC = 15 cm Area of triangle ADC, say A2 having sides a, b, c and s as semi-perimeter is given by , where a = AD = 9 cm; b = DC = 12 cm; c = AC = 15 cm Area of quadrilateral ABCD, say A A = Area of ∆ACB + Area of ∆ADC Perimeter of quadrilateral ABCD, say P |
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