1.

Find the area of the ellipse ax^2 + 2hxy + by^2 = 1​

Answer»

ANSWER:

Prove that the area of the ELLIPSE

Ax2+2Bxy+Cy2+2Dx+2Ey+F=0,Ax2+2Bxy+Cy2+2Dx+2Ey+F=0,

where AC−B2>0AC−B2>0, is EQUAL to

S=−πΔ(AC−B2)3/2,S=−πΔ(AC−B2)3/2,

where

Δ=∣∣∣∣ABDBCEDEF∣∣∣∣.Δ=|ABDBCEDEF|.

I COULD prove that area of ellipse x2a2+y2b2=1x2a2+y2b2=1 is πab

Step-by-step explanation:

please follow me



Discussion

No Comment Found

Related InterviewSolutions