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Find the area of rhombus in which AB5 cm and AC8 cm.5 cm |
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Answer» ABCD is the given rhombus. Side AB = BC = CD = DA = 5cm One diagonal AC = 8cm In right ∆ABD, we have to calculate diagonal BD Using pythagoras theorem, BD^2 = AB^2 + AD^2 = (5)^2 + (5)^2 = 25+25BD = 25√2cm area of rhombus = 1/2* (8)* (25√2) = 4*25√2 = 100√2 cm^2 |
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