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Find the area of quadrilateral abcd ,has ab=3cm,bc=4cm,cd=4cm,da=5cmand,ac=5cm |
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Answer» AB = 3cm bc = 4cm cd = 4cm ad = 5cm ac = 5cm Pythagoras theorem says c^2 = a^2 + b^2 c = ac = 5cm a = ab = 3cm b = bc = 4cm c^2 = (5cm)^2 a^2 = (3cm)^2 b^2 = (4cm)^2 25 = 9 + 16 So it is a right angle. A = (b×h)/2 A = (3×4)/2 = 12/2 = 6cm abc = 6cm A of TRIANGLE = √s(s-a)(s-b)(s-c) s = (a+b+c)/2 s = (5+5+4)/2 = 14/2 = 7 √7(7-5)(7-5)(7-4) √7×2^2×3 2√21cm 6+2√21cm 8√21cm I HOPE it is CORRECT ... With regards Achyuta Shrimate |
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