Find the area of isosceles triangle if medians are 24, 18 and 18

1.	Find the area of isosceles triangle if medians are 24, 18 and 18
Answer» ong>Answer: According to the Heron's FORMULA, Area (A) of the triangle having SIDES a,b,c units is A=s(s−a)(s−b)(s−c) where s=2a+b+c For the given triangle, a=18 CM b=24 cm c=30 cm s=218+24+30=36 A=36(36−18)(36−24)(36−30) A=36×18×12×6 A=216×216 =216 cm2 Smallest side =18 cm Area of the triangle =21×base×altitude=216 21×18× altitude=216 Altitude =9216=24 cm

Answer»

ong>Answer:

According to the Heron's FORMULA, Area (A) of the triangle having SIDES a,b,c units is

A=s(s−a)(s−b)(s−c)

where

s=2a+b+c

For the given triangle,

a=18 CM

b=24 cm

c=30 cm

s=218+24+30=36

A=36(36−18)(36−24)(36−30)

A=36×18×12×6

A=216×216

=216 cm2

Smallest side =18 cm

Area of the triangle =21×base×altitude=216

21×18× altitude=216

Altitude =9216=24 cm

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Find the area of isosceles triangle if medians are 24, 18 and 18​

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Find the area of isosceles triangle if medians are 24, 18 and 18