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Find the area of isoceles triangle whose equal side is 6cm,6cm and 8cm |
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Answer» Step-by-step explanation: Given : Two EQUAL sides of an isosceles TRIANGLE are 6cm each. Third side of the triangle is 8cm. To Find : Area of the isosceles triangle. Solution : a = 6cm. b = 6cm. c = 8cm. \longmapsto\tt{s=\dfrac{a+b+c}{2}}⟼s= 2 a+b+c
\longmapsto\tt{s=\dfrac{6+6+8}{2}}⟼s= 2 6+6+8
\longmapsto\tt{s=\cancel\dfrac{20}{2}}⟼s= 2 20
\longmapsto\tt\bold{s=10cm}⟼s=10cm Now , \longmapsto\tt{Area=\sqrt{s(s-a)(s-b)(s-c)}}⟼Area= s(s−a)(s−b)(s−c)
\longmapsto\tt{\sqrt{10(10-6)(10-6)(10-8)}}⟼ 10(10−6)(10−6)(10−8)
\longmapsto\tt{\sqrt{10\times{4}\times{4}\times{2}}}⟼ 10×4×4×2
\longmapsto\tt{\sqrt{5\times{2}\times{2}\times{2}\times{2}\times{2}\times{2}}}⟼ 5×2 ×2×2×2×2×2
\longmapsto\tt{2\times{2}\times{2}\sqrt{5}}⟼2×2×2 5
\longmapsto\tt\bold{8\sqrt{5}{cm}^{2}}⟼8 5
cm 2
So , The Area of the isosceles triangle is 8√5cm² This is your answer.༎ຶ‿༎ຶ |
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