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Find the area of and the perimeter of Rho whose diagonals are 10 cm and 12 cm |
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Answer» area of rhombus = product of digonal/2so area is = 10×12 / 2 = 60cm²Rhombus digonal bisect each other also at 90°, so we can find third using pythaogras theoremLet third side be x5² + 6² = x²25+36 = x²61 = x²x = √61Perimeter of rhombus = is 4 × side = 4× √61 = 4√61 cm |
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