Find the area of a triangle whose sides are 18 cm, 10 cm and 14 cm.

1.	Find the area of a triangle whose sides are 18 cm, 10 cm and 14 cm.
Answer» GIVEN: A = 18cm B=10cm C=14 cm To FIND: area of a TRIANGLE .•♫•♬•Solution •♬•♫•. $semi \: perimeter \: = \frac{a + b + c}{2}$ $semi \: perimeter = \frac{18 + 10 + 14}{2}$ $semi \: perimeter \: = \frac{42}{2} = 21$ By heron's formula $\sqrt{S(S - a)(S - b)(S - c)}$ $\sqrt{21 (\: 21 - 18)(21 - 10)(21 - 14}$ $\sqrt{21 \times 3 \times 11 \times 7}$ We can also write 21 as 7× 3 $\sqrt{7 \times 3 \times 3 \times 11 \times 7}$ $\sqrt[21]{11}$ Hence the area of triangle is 21√11

Answer»