Find the area of a triangle two sides of which are 18 cm and 14cm and

1.	Find the area of a triangle two sides of which are 18 cm and 14cm and the perimeter is 42cm
Answer» ANSWER: $Area of triangle s(s−a)(9−b)(s−0) Here, s is the semi- perimeter,and a,b,c are the sides of the triangleGiven a=18 cm, b=10 cmand perimeter =42 cmsemi- perimeters= 2perimeter = 242 s=21cm.Area of triangle ∴c=42−(18+10)cm =14 cm∴ Area of triangle= 21.(21−18)(21−10)(21−14) = 21.3.7.11 cm 2 = 3×7×3×7×11 cm 2 = (3×7) 2 ×11 cm 2 =21 11 cm 2 ∴ Thus, the required area of the triangle is 21 11 cm 2$ Step-by-step EXPLANATION:

Find the area of a triangle two sides of which are 18 cm and 14cm and the perimeter is 42cm

Answer»

$Area of triangle s(s−a)(9−b)(s−0) Here, s is the semi- perimeter,and a,b,c are the sides of the triangleGiven a=18 cm, b=10 cmand perimeter =42 cmsemi- perimeters= 2perimeter = 242 s=21cm.Area of triangle ∴c=42−(18+10)cm =14 cm∴ Area of triangle= 21.(21−18)(21−10)(21−14) = 21.3.7.11 cm 2 = 3×7×3×7×11 cm 2 = (3×7) 2 ×11 cm 2 =21 11 cm 2 ∴ Thus, the required area of the triangle is 21 11 cm 2$

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Find the area of a triangle two sides of which are 18 cm and 14cm and the perimeter is 42cm​

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Find the area of a triangle two sides of which are 18 cm and 14cm and the perimeter is 42cm