1.

Find the area of a triangle if its two sides are 18 cm and 10 cm and the perimeter is 42 CM

Answer»

Perimeter of TRIANGLE=P=42 cm
sides of triangle a=18cm, b=10cm & C=?

P=a+b+c
42=18+10+c
c=42-28
c=14cm

Semiperimeter, S= P/2= 42/2=21cm

Area = √21(21-18)(21-10)(21-14)
= √21*3*11*7
=√7*7*3*3*11
=7*3√11
=21√11 sqcm

hope it is useful



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