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Find the area of a trapezium,lengths of whose parallel sides are 13 cm and 11 cm and the distance between them is 14 cm: (explain in detail)​ with formula​

Answer»

Answer:

168cm

Step-by-step EXPLANATION:

LET the LENGTH of the parallel sides be, b_{1}  = 13cm and b_{2} = 11cm

h =14cm

therefore, area of trapezium

=\frac{(b_{1} + b_{2}) ({h}) }{2} \\= \frac{(13 + 11) X (14)}{2} \\=\frac{24 X 14}{2} = \frac{336}{2} =168



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