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Find the area of a rhombus whose one side measures 5 cm and one diagonal as 8 cm.Please solve this question |
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Answer»
• Area of the Rhombus is 24cm²
According to the Question It is GIVEN that ,
we have to calculate the area of rhombus . As we know that all sides in rhombus are EQUAL in length . Firstly we calculate the another diagonal of rhombus . As we know that diagonal are perpendicular bisector in rhombus . So we apply here the Pythagoras Theorem for calculating the another diagonal of the rhombus . half of diagonal = 8/2 = 4cm Let the another diagonal be x centimetres ➻ x² + 4² = 5² ⠀⠀⠀----(by Pythagoras Theorem) ➻ x² + 16 = 25 ➻ x² = 25-16 ➻ x² = 9 ➻ x = √9 ➻ x = 3 cm Length of another diagonal = 2 × 3 = 6cm Now, calculating the area of the rhombus .
Putting the value we get ➻ Area of Rhombus = 1/2 × 8× 6 ➻ Area of Rhombus = 1/2 × 48 ➻ Area of Rhombus = 48/2 ➻ Area of Rhombus = 24 cm²
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