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find the area of a regular pentagon whose each side is 5 cm long and the radius of the Scribe circle is 3.5 CM solve it please please. |
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Answer» Let US find the area of one of the 5 isosceles triangles in the pentagon. Side of pentagon a = 5cm PERPENDICULAR DISTANCE between CENTRE of pentagon and the side = 3.5 cm Area of the traingle = (1/2)*5*3.5 = 8.75 cm² Therefore, area of pentagon = 8.75 * 5 = 43.75 cm² |
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