Find the area of a parallelogram formed by vectorsÅ=3icap+2jcap, B=-3

1.	Find the area of a parallelogram formed by vectorsÅ=3icap+2jcap, B=-3icap+7jcap
Answer» $\mathfrak{\large{\underline{\underline{Answer:-}}}}$ $\mathfrak{\large{\underline{\underline{Given:-}}}}$ → A = 3 I + 2 j → B = 3 I + 7 j $\mathfrak{\large{\underline{\underline{To find:-}}}}$ Area of PARALLELOGRAM= ? $\mathfrak{\large{\underline{\underline{Solution:-}}}}$ We know, that area of parallelogram = ★ $\boxed{\sf{ A × B}}$ area of parallelogram = $\bold{(3i + 2j) \: \times \: ( - 3i \: + 7j) }$ ★ $\boxed{\sf{i × i = 0}}$ ★ $\boxed{\sf{i × j = 0}}$ ★ $\boxed{\sf{ I × j = k}}$ ★ $\boxed{\sf{ j × I = -k}}$ = $\bold{3i \times ( - 3i) + 3i \times 7j + 2j \times ( - 3i) + 2j \times 7j}$ = $\bold{ 0 + 21k - 6(-k) + 0}$ = $\bold{<klux>27</klux> k}$ hence, area of parallelogram is 27 SQ. UNITS