1.

Find the approximate value of 8.95

Answer»

Let f(x) = sqrt(x)f'(x) = d/dx [ sqrt(x) ] = d/dx [x^(1/2) ] = (1/2) x^(-1/2) = 1 / 2 x^(1/2) = 1 / 2sqrt(x)

Let x=9sqrt(9)=3

sqrt(8.95)= f(8.95)= f(9) + (8.95-9) f'(9)= 3 + (-0.05) [1 / 2 sqrt(9)]= 3 - 0.05 / 6= 2.991667



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