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find the AP. (3,5,7,9,...20: How many three digit natural numbers are divisible by 77 (128)L tr. 11 Its 2つth term rs three times Its 8th te21

Answer»

The first three digit number which is divisible by 7 is 105 and last three digit number which is divisible by 7 is 994.

This is an A.P. in which a = 105, d = 7 and l = 994.

Let the number of terms be n . Then tn = 994.

nth term of A.P tn = a + (n - 1)d.

994 = 105 + (n -1)7.

889 = 7(n-1)

n -1 = 127

n = 128.

Hence, There are 128 three digit numbers which are divisible by 7.



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