Saved Bookmarks
| 1. |
Find the angles between the lines √3x + y = 1 and x + √3y = 1 . |
|
Answer» Its angles and 1 angle m1=-√3m2=-1/√3Tan¢=(m2-m1)/1+m1m2=(-1/√3+√3)/1+12/2√31/√3¢= π/6 |
|