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| 1. |
Find the angle of deviation suffered by the light ray shown in figure (18-E10). The refractive index μ = 1.5 for the prism material. |
| Answer» ANGLE of prism = A =4°Refractive index of prism = 1.5Angle of deviation = d=?FORMULA to be USED :μ= SIN(A+dm)/2/ Sin A/2for small angle of prism sinθ=θso,1.5= (4+dm)/2)/ 4/21.5 X 4= 4+dmdm= 1.5x 4° -4°=4x 0.5=4x5/10=2°∴Angle of deviation =dm=2° | |