1.

Find the angle between two vectors vector A is equal to i cap +2j cap -kcap amd vector B is equal to -icap -2jcap +k cap

Answer»

Answer:

A=2 i + 2 j - 1 k and B = 6 i - 3 j + 2 k (Bold denotes VECTORS and i, j, and k are unit vectors in the x, y and z directions, RESPECTIVELY). Then the dot (scalar) product is;

A . B = |A| |B| cos(THETA) and A . B = 2 x 6 -2 x 3 - 1 x 2 = 4 , |A| = 3 and |B| = 7

and we get 4 = 3 x 7 cos(theta). Solving, cos(theta) = 4/21 = 0.19

Finally, theta = 79 degrees.

hope this will HELPS you.....

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