Find the angle between the vectors : vector a =3i - 4j and vector b =

1.	Find the angle between the vectors : vector a =3i - 4j and vector b = -2i+3k
Answer» $\:\:\:\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \huge\mathcal{\bf{{\underline{\underline{\huge\mathcal{...Answer...}}}}}}$ $\underline{\large\mathcal\red{solution}}$ a =3i - 4j and vector B = -2i+3k now ...\|a\|=√[(3)²+(-4)²]=5 and.....\|b\|=√[(-2)²+(3)²]=√13 now the DOT PRODUCT of a and b is a.b=-6-12=-18 the angle is $\cos {}^{ - 1} ( \frac{ - 18 }{ 5 \sqrt{13} } )$ =3.09° $\large\mathcal\red{hope\: this \: helps \:you......}$