1.

Find the angle between the lines 2x²+2√17xy+4y²=0​

Answer»

Step-by-step explanation:

Let the SLOPE of pair of LINES represented by the EQUATION 2{x}^{2}+2\sqrt{17}xy + 4y^{2} be m_{1} & m_{2}

Now,

m_{1} + m_{2} = - \sqrt{17} \implies m_{1} - m_{2} = 3\\ m_{1}m_{2} = 2

Required ANGLE

\tan( \theta) = \frac{ | m_{1} - m_{2} | }{1 +m_{1}m_{2}} \\

\tan( \theta) = \frac{ 3 }{1 +2} \\

\implies \: \theta = \frac{\pi}{4} \\


Discussion

No Comment Found

Related InterviewSolutions