Find the amount on Rs 1200 taken for 2 years at 4% p.a. compounded qua

1.	Find the amount on Rs 1200 taken for 2 years at 4% p.a. compounded quarterly.
Answer» $Here, we \: are \: given, \\ \\ Principle \: (P) = 1200 Rs \\ Time \: (n) = 2 \: year \\ Rate \: of \: Interest \: (r) = 4\times \frac{1}{100} = \frac{4}{100} \\ Compound \: Amount \: (C) = ?$ ☆ _____________________________________________ ☆ $As, we \: know \: that, C = P (1+r)^{n} \\ So, C = 1200 \times (1 + \frac{4}{100} )^{2} \\ . \: \: \: \: \: \: \: \: \: = 1200 \times (1 + 25) ^{2} \\ . \: \: \: \: \: \: \: \: \: = 1200 \times {26}^{2} \\ . \: \: \: \: \: \: \: \: \: = 1200 \times 676 \\ . \: \: \: \: \: \: \: \: \: = 811200$ $Answer: Compound \: of \:\: Interest\: \: is \: 811200 \: Rs.$ ꧁________________________♡________________________꧂ ❤ $I \: hope \: you \: will \: be \: helped \: by \: my \: answer. \\Please \: Follow \: Me\: and \: Mark \: As \: Brainliest.$ ❤

Find the amount on Rs 1200 taken for 2 years at 4% p.a. compounded quarterly.

Answer»

$Here, we \: are \: given, \\ \\ Principle \: (P) = 1200 Rs \\ Time \: (n) = 2 \: year \\ Rate \: of \: Interest \: (r) = 4\times \frac{1}{100} = \frac{4}{100} \\ Compound \: Amount \: (C) = ?$

☆ _____________________________________________ ☆

$As, we \: know \: that, C = P (1+r)^{n} \\ So, C = 1200 \times (1 + \frac{4}{100} )^{2} \\ . \: \: \: \: \: \: \: \: \: = 1200 \times (1 + 25) ^{2} \\ . \: \: \: \: \: \: \: \: \: = 1200 \times {26}^{2} \\ . \: \: \: \: \: \: \: \: \: = 1200 \times 676 \\ . \: \: \: \: \: \: \: \: \: = 811200$