1.

Find the amount of carbon needed to produce 683 g of Ni(CO)4. C+CO2→CO (Yield of reaction = 70 %) Ni+4CO→Ni(CO)4 (Yield of Mond’s process = 20 %) (Molar mass of Nickel = 58.7 g/mol)

Answer»

Find the amount of carbon needed to produce 683 g of Ni(CO)4.
C+CO2CO (Yield of reaction = 70 %)
Ni+4CONi(CO)4 (Yield of Mond’s process = 20 %)
(Molar mass of Nickel = 58.7 g/mol)



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