A=p[ (1+r/n)^nt +1]= 2500 [( 1+8/4)^4×1+1]= [3^4 +1] ×2500=[ 81+1]×2500=82 ×2500Amoubt =205000

( Given principle amt =2500Rsquaterly so n =41year so t=1r=8%)

200 repees is the answer

interest calculated quarterly,

rate becomes 1/4 times,rate = 8/4 = 2%

time become 4 times, time = 1 x 4 = 4

Amount = p(1+R/100)^n

= 2500(1+2/100)^4

= 2500(51/50)^4

= 2500(1.02)^4

= 2706.08 rs..

compound Interest = amount - principal = 2706.08 - 2500 = 206.08 rs.. (ANS)

The correct answer of this question is :- 200 rupees.

A=P(1+R/100)^n

since c.i is calculated qurterly then n=4and, rate=8/4=2%so, A=2500(1+2/100)^4A=2500(1+2/100)^4A=2500×(102/100)^4A=2706.08 rs.hence C.I.=A-P =2706.08-2500 =206.08 rs. ans.

Given,Principal=₹2500Rate=8%p.a.Time=1 yearThen,=Amount=P(1+R/100)power 2=2500(1/1 + 8/100) power 2=2500(108/100)power 2. {by taking LCM)=2500×108×108/100×100=₹2916A=₹2916CI=A-P=2916-2500=₹416

Rs 206.08 is the compound interest

2500*1*8/1002500*8/10020000/100200

The answer is 8% That should be answered by the formulas

I=ptr/100=2500×1×8/100=200compound interest is 2500+200=2700

R = 8%May this help you

200 is the correct answer. please like as best

C. I=2706.08 is a correct answer

500×8÷100 equals to 200

answers are given why should i give

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The correct answer is r=8%.