1.

Find the absolute extrema values of g(t)=t-t^(4 ) on [-2,1]​

Answer»

Step-by-step explanation:

g(t)=t-t^(4 )

g(-2)= -2-(-2)^4

g(-2)= -2-16

g(-2)= -18

g(t)=t-t^(4 )

g(1)= 1-1^4

g(1)= 1-1

g(1)= 0



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