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Find the (a) maximum frequency and (b) minimum wavelength of X-rays produced by 30 kv electrons. |
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Answer» Given V = 30 kV = 30 × 103 volt Energy, E = eV = 1.6 × 10–19 × 30 × 103 = 4.8 × 10–15 joule (a) Maximum Frequency vmax is given by, E = hvmax vmax = E/h = (4.8 x 10-15/6.63 x 10-34 ) = 7.24 x 1018 Hz (b) Minimum wavelength,λmin = c/Vmax = 3x 108/7.28 x1018 = 4.1 × 10–11 m = 0.041 nm |
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